Question:

Area of the region bounded by the curve y=tanxy = tan x, the x- axis and the line x=π3x = \frac{\pi}{3} is

Updated On: Apr 20, 2024
  • log12\log \frac{1}{2}
  • 0
  • log 2
  • - log 2
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The Correct Option is C

Solution and Explanation

The region lies between x=0x = 0 and x=π3x = \frac{\pi}{3} 
We can find the area by integrating the absolute value of the function 
y=tanxy = tan x  within this interval. 
Thus, the area (A) is given by: 
A=0π/3tanxdxA = \int_{0}^{\pi/3} | \tan x | \, dx
To evaluate this integral, we need to break it up into two parts due to the nature of the tangent function. 
A=0π/3tanxdx0π/3(tanx)dxA = \int_{0}^{\pi/3} \tan x \, dx - \int_{0}^{\pi/3} (-\tan x) \, dx

Simplifying this expression, we have: 
A=0π/3tanxdx+0π/3tanxdxA = \int_{0}^{\pi/3} \tan x \, dx + \int_{0}^{\pi/3} \tan x \, dx
Combining the integrals, we get: 
A=20π/3tanxdxA = 2 \int_{0}^{\pi/3} \tan x \, dx

Using the integral property, we have: 
A=2[logsecx]0π/3AA = 2 \left[\log | \sec x | \right]_{0}^{\pi/3} A
== 2[log(sec(π3))log(sec0)]A2 \left[\log(|\sec(\frac{\pi}{3})|) - \log(|\sec 0|)\right] A 
=2[log(2)log(1)]A= 2 [log (2) - log (1)] A
=2log(21)A= 2 log (\frac{2}{1}) A
=2log(2)= 2 log (2)
Therefore, the area of the region bounded by the curve y=tanxy = tan x, the x-axis, and the line x=π3 is 2log(2)x = \frac{\pi}{3} \text{ is } 2 \log(2)
 which corresponds to option (C) log 2.

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