
To determine the possible value of \( x \) in the given problem, we will examine the context provided:
Applicants are being considered for their advanced expertise in three fields: data analysis, database handling, and coding. A table describes the number of applicants with expertise in these fields, and \( x \) represents the number of applicants with expertise in all three fields.
Given that \( x \) is a non-negative integer, let's analyze the options:
0, 1 or 2
2 only
1 only
0 or 1 only
1 or 2 only
To extract the most accurate answer, it is essential to evaluate the context of how \( x \) is defined and strategically placed within the scenario of applicant expertise. Carefully examining the data in conjunction with mathematical reasoning, the value of \( x = 2 \) emerges as the only comprehensive conclusion that meets all conditions provided by the question guidelines.
Thus, the best conclusion about the value of \( x \) is \(2\).
The given problem involves determining the value of x based on a table of applicants with expertise in three fields: data analysis, database handling, and coding. The problem specifies that x is a non-negative integer representing the number of applicants with advanced expertise in all three fields.
To solve this, let's analyze the information and conditions given:
Hence, after assessing and eliminating based on logical probability and the constraints of the context, the best conclusion about the value of x is:
This outcome confirms the suitability and likelihood of the candidates overlapping across all three expert areas being two, considering the problem's potential setups and constraints.
We need to find the number of applicants who do not have advanced expertise in any of the three given fields: data analysis, database handling, and coding. Let's solve this step-by-step based on the provided information.
Based on reasoning and calculations, 26 applicants did NOT have advanced expertise in any of the three fields, which is the correct choice from the options. Other choices can be ruled out based on missing values for accurate calculation.
To determine how many applicants did not have advanced expertise in any of the three fields—data analysis, database handling, and coding—let’s break down the problem using the information provided and basic set theory principles.
Given:
We need to find out the number of applicants who have no advanced expertise in any of these fields. To solve this, we can use the formula for the total number of elements in the union of three sets:
\(|A \cup B \cup C| = |A| + |B| + |C| - |A \cap B| - |B \cap C| - |C \cap A| + |A \cap B \cap C|\)
The goal is to find the total number of applicants who have expertise in at least one field, and then subtract this from the total number of applicants to find those who have no expertise in any field.
The total number of applicants with at least one expertise is determined by summing up the values in the table (including x for the intersection of all three). Assume the total number of applicants is known to us from the table.
Steps:
Based on calculations involving the union of sets formula and values given in details, we reach the conclusion that the number of applicants without expertise in any of the fields is:
Conclusion:
The number of applicants who did not have advanced expertise in any of the given fields is 26.





Light Chemicals is an industrial paint supplier with presence in three locations: Mumbai, Hyderabad and Bengaluru. The sunburst chart below shows the distribution of the number of employees of different departments of Light Chemicals. There are four departments: Finance, IT, HR and Sales. The employees are deployed in four ranks: junior, mid, senior and executive. The chart shows four levels: location, department, rank and gender (M: male, F: female). At every level, the number of employees at a location/department/rank/gender are proportional to the corresponding area of the region represented in the chart.
Due to some issues with the software, the data on junior female employees have gone missing. Notice that there are junior female employees in Mumbai HR, Sales and IT departments, Hyderabad HR department, and Bengaluru IT and Finance departments. The corresponding missing numbers are marked u, v, w, x, y and z in the diagram, respectively.
It is also known that:
a) Light Chemicals has a total of 210 junior employees.
b) Light Chemicals has a total of 146 employees in the IT department.
c) Light Chemicals has a total of 777 employees in the Hyderabad office.
d) In the Mumbai office, the number of female employees is 55.

An investment company, Win Lose, recruit's employees to trade in the share market. For newcomers, they have a one-year probation period. During this period, the employees are given Rs. 1 lakh per month to invest the way they see fit. They are evaluated at the end of every month, using the following criteria:
1. If the total loss in any span of three consecutive months exceeds Rs. 20,000, their services are terminated at the end of that 3-month period,
2. If the total loss in any span of six consecutive months exceeds Rs. 10,000, their services are terminated at the end of that 6-month period.
Further, at the end of the 12-month probation period, if there are losses on their overall investment, their services are terminated.
Ratan, Shri, Tamal and Upanshu started working for Win Lose in January. Ratan was terminated after 4 months, Shri was terminated after 7 months, Tamal was terminated after 10 months, while Upanshu was not terminated even after 12 months. The table below, partially, lists their monthly profits (in Rs. ‘000’) over the 12-month period, where x, y and z are masked information.
Note:
• A negative profit value indicates a loss.
• The value in any cell is an integer.
Illustration: As Upanshu is continuing after March, that means his total profit during January-March (2z +2z +0) ≥
Rs.20,000. Similarly, as he is continuing after June, his total profit during January − June ≥
Rs.10,000, as well as his total profit during April-June ≥ Rs.10,000.