Anil takes out a loan of Rs 2 lakhs, with interest compounded every six months at a rate of 8% per year.
It is also known that at the conclusion of the first year, he repays Rs 10,320, and at the end of the third year, he terminates the debt by making the final payment.
At the conclusion of the first year, the total amount can be calculated as follows:
\(200000 \times \frac{104}{100} \times \frac{104}{100} = 216320\)
Thus, after one year, the total amount due becomes Rs 216,320.
At the end of the first year, Anil repays Rs 10,320. Therefore, the remaining outstanding balance is:
Outstanding balance = Rs 216,320 - Rs 10,320 = Rs 206,000.
The interest will continue to be charged on the outstanding balance of Rs 206,000 for a further two years. The total amount after three years is calculated as:
\(206000 \times \left(\frac{104}{100}\right)^4 = 240990.86\)
So, the total amount due at the end of the third year is Rs 240,990.86.
The interest accrued over the next two years is:
\(240990.86 - 206000 = 34990.86\)
The total interest accumulated over the three years is the sum of the interest for the first year and the next two years:
\(34990.86 + 16320 = 51311\)
The total interest accumulated over the three years is Rs 51,311.
When $10^{100}$ is divided by 7, the remainder is ?