Question:

An α particle and a proton are accelerated from rest through the same potential difference. The ratio of linear momenta acquired by above two particles will be:

Updated On: Sep 13, 2024
  • √2:1
  • 2√2:1
  • 4√2:1
  • 8:1
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The Correct Option is B

Solution and Explanation

The ratio of linear momenta acquired by above two particles,
\(\frac{pα}{pp}=\frac{\sqrt{2(4m)(2eV)}}{{\sqrt{2(m)(eV)}}}\)
\(=\frac{\sqrt{16}}{√2}\)
=\(\frac{4}{√2}\)
\(=\frac{2√2}{1}\)
So, the correct option is (B): \(\frac{2√2}{1}\)

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