We are given that the block is rotating in a horizontal circle, and the centripetal acceleration is equal to \( g \), the acceleration due to gravity.
### Step 1: Formula for Centripetal Acceleration
The centripetal acceleration \( a_c \) of an object moving in a circle of radius \( R \) with angular velocity \( \omega \) is given by:
\[
a_c = R \omega^2
\]
### Step 2: Set Centripetal Acceleration Equal to \( g \)
We are told that the centripetal acceleration is equal to \( g \), so:
\[
g = R \omega^2
\]
### Step 3: Solve for Angular Velocity \( \omega \)
Solving for \( \omega \), we get:
\[
\omega = \sqrt{\frac{g}{R}}
\]
Thus, the correct answer is:
\[
\boxed{(C) \, \omega = \sqrt{\frac{g}{R}}}
\]