Question:
An organ pipe 40cm long is open at both ends. The speed of sound in air is 360ms-1 . The frequency of the second harmonic is ____Hz.
An organ pipe 40cm long is open at both ends. The speed of sound in air is 360ms-1 . The frequency of the second harmonic is ____Hz.
Updated On: Mar 19, 2025
Hide Solution
Verified By Collegedunia
Correct Answer: 900
Solution and Explanation
Step 1: Formula for frequency in an open organ pipe.- Fundamental frequency f1 = $\frac{v}{2L}$, where v = 360m/s, L = 0.4m.- Frequency of second harmonic f2 = 2f1.
Step 2: Calculate the frequency.
f1 = $\frac{360}{2 \times 0.4}$ = 450Hz.
f2 = 2 × 450 = 900Hz.
Final Answer: The frequency of the second harmonic is 900Hz
Was this answer helpful?
0
0
Top Questions on sound
- The fundamental frequency of a closed organ pipe of length \( 20 \, \mathrm{cm} \) is equal to the second overtone of an organ pipe open at both ends. What is the length of the organ pipe open at both ends?
- A point source is placed at origin. Its intensity at distance of 2 cm from source is I then intensity at distance 4 cm from the source shall be.
- Which of the following is a transducer ?
(A) Loudspeaker
(B) Amplifier
(C) Rectifier
(D) Microphone
Choose the correct answer from the options given below : - The ratio of the speed of sound in hydrogen gas to the speed of sound in oxygen gas at the same temperature is:
- The velocity of sound in a gas, in which two wavelengths, 4.08 m and 4.16 m produce 40 beats in 12 s, will be:
View More Questions
Questions Asked in JEE Main exam
- What are the units of viscosity, intensity of wave, and pressure gradient?
- JEE Main - 2025
- Units and measurement
- If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
- JEE Main - 2025
- Matrices and Determinants
- Let \( P_n = \alpha^n + \beta^n \), \( P_{10} = 123 \), \( P_9 = 76 \), \( P_8 = 47 \), and \( P_1 = 1 \). The quadratic equation whose roots are \( \frac{1}{\alpha} \) and \( \frac{1}{\beta} \) is:
- JEE Main - 2025
- Sequences and Series
- The distance of the point \( P(1, 2, 3) \) from the plane \( 3x - 4y + 12z - 7 = 0 \) is:
- JEE Main - 2025
- Geometry and Vectors
- A concave mirror produces an image of an object such that the distance between the object and image is 20 cm. If the magnification of the image is \( -3 \), then the magnitude of the radius of curvature of the mirror is:
- JEE Main - 2025
- Spherical Mirrors
View More Questions