\(\frac{2}{T}\)
\(\frac{3}{T}\)
\(\frac{1}{2T}\)
\(\frac{1}{T}\)
Given:
\[ \frac{dV}{V} = \alpha \frac{dT}{T} \]
For a constant \( P T^2 \), we have:
\[ \frac{dV}{dT} = \left( C \right) \frac{3}{T^2} \]
So, the volume expansion coefficient is:
\[ \frac{dV}{V} = \frac{3}{T^2} \cdot dT \]
List - I | List -II | ||
---|---|---|---|
a | Isothermal | i | Pressure constant |
b | Isobaric | ii | Temperature constant |
c | Adiabatic | iii | Volume constant |
d | Isobaric | iv | Heat content is constant |
Let \( A = \{-3, -2, -1, 0, 1, 2, 3\} \). A relation \( R \) is defined such that \( xRy \) if \( y = \max(x, 1) \). The number of elements required to make it reflexive is \( l \), the number of elements required to make it symmetric is \( m \), and the number of elements in the relation \( R \) is \( n \). Then the value of \( l + m + n \) is equal to: