Question:

An ideal gas undergoes a thermodynamic process following the relation PT2 = constant. Assuming symbols have their usual meaning then volume expansion coefficient of the gas is equal to

Updated On: Jan 17, 2025
  • \(\frac{2}{T}\)

  • \(\frac{3}{T}\)

  • \(\frac{1}{2T}\)

  • \(\frac{1}{T}\)

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The Correct Option is B

Solution and Explanation

Given: 

\[ \frac{dV}{V} = \alpha \frac{dT}{T} \]

For a constant \( P T^2 \), we have:

\[ \frac{dV}{dT} = \left( C \right) \frac{3}{T^2} \]

So, the volume expansion coefficient is:

\[ \frac{dV}{V} = \frac{3}{T^2} \cdot dT \]

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