Question:

An ideal fluid of density 800kgm–3, flows smoothly through a bent pipe (as shown in figure) that tapers in cross-sectional area from a to a2\frac{a}{2}. The pressure difference between the wide and narrow sections of pipe is 4100 Pa. At wider section, the velocity of fluid isx6\frac{\sqrt{x}}{6} ms1 for x=_______. (Given g=10 ms-2)
ideal fluid of density 800kgm–3

Updated On: Sep 24, 2024
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Correct Answer: 363

Solution and Explanation

Applying Bernoulli’s theorem: P1+ρgh+12ρv2=P2+12ρ(2v)2P_1 + \rho g h + \frac{1}{2} \rho v^2 = P_2 + \frac{1}{2} \rho (2v)^2

Putting the values, 4100=800(32v210)4100=800(\frac{3}{2}v^2−10)
v=3636m/s⇒v=\frac{\sqrt{363}}{6}m/s

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