
Applying Bernoulli’s theorem: \(P_1 + \rho g h + \frac{1}{2} \rho v^2 = P_2 + \frac{1}{2} \rho (2v)^2\)
Putting the values, \(4100=800(\frac{3}{2}v^2−10)\)
\(⇒v=\frac{\sqrt{363}}{6}m/s\)
For a statistical data \( x_1, x_2, \dots, x_{10} \) of 10 values, a student obtained the mean as 5.5 and \[ \sum_{i=1}^{10} x_i^2 = 371. \] He later found that he had noted two values in the data incorrectly as 4 and 5, instead of the correct values 6 and 8, respectively.
The variance of the corrected data is: