Question:
An equilateral prism of mass $m$ rests on a rough horizontal surface with coefficient of friction $\mu$.
An equilateral prism of mass $m$ rests on a rough horizontal surface with coefficient of friction $\mu$.
Updated On: Jan 30, 2025
- $\frac{mg}{\sqrt{3}}$
- $\frac{mg}{4}$
- $\frac{\mu mg}{\sqrt{3}}$
- $\frac{\mu mg}{4}$
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The Correct Option is A
Solution and Explanation
The tendency of rotation will be about the point C.
For minimum force, the torque of F about C has to be equal to the torque of mg about C.
$\therefore F\left(a \frac{\sqrt{3}}{2}\right) = mg \left(\frac{a}{2}\right) \Rightarrow F = \frac{mg }{\sqrt{3}}$
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Concepts Used:
Torque
Torque is a moment of force. Torque is measured as a force that causeque is also defined as the turning effect of force on the axis of rotation. Torque is chs an object to rotate about an axis and is responsible for the angular acceleration. Characterized with “T”.
How is Torque Calculated?
Torque is calculated as the magnitude of the torque vector T for a torque produced by a given force F
T = F. Sin (θ)
Where,
r - length of the moment arm,
θ - the angle between the force vector and the moment arm.
Read More: Torque
Types of Torque
Torque is of two types:
- Static torque
- Dynamic torque