Question:

An ellipse has lengths of major and minor axes as 6 and 2 respectively. If the center is at \( (5,6) \) and the major axis lies along the line \( x - y + 1 = 0 \), then the equation of the ellipse is:

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Ellipse with Inclined Axes}
Use rotation transformation: \( u = x + y, v = x - y \)
Replace variables in standard ellipse form
Remember: \( a = \frac{1}{2} \times \text{major axis length} \)
Updated On: May 19, 2025
  • \( (x + y - 11)^2 + 9(x - y + 1)^2 = 18 \)
  • \( (x + y + 11)^2 + 9(x - y - 1)^2 = 18 \)
  • \( (x + y)^2 + 9(x - y)^2 = 18 \)
  • \( (x - y - 11)^2 + 9(x + y + 1)^2 = 18 \)
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The Correct Option is A

Solution and Explanation

Major axis length = 6 ⇒ semi-major axis \( a = 3 \) Minor axis length = 2 ⇒ semi-minor axis \( b = 1 \) Direction of major axis = along \( x - y + 1 = 0 \Rightarrow \) line rotated Transform coordinates: \[ u = x + y,\quad v = x - y \Rightarrow \text{Major axis along } v,\quad minor axis along \( u \) \] Standard ellipse: \[ \frac{v^2}{a^2} + \frac{u^2}{b^2} = 1 \Rightarrow \frac{(x - y + 1)^2}{9} + (x + y - 11)^2 = 1 \Rightarrow \text{Clear LCM: } (x + y - 11)^2 + 9(x - y + 1)^2 = 18 \]
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