Question:

An artificial cell is made by encapsulating \(0.2 \, \text{M}\) glucose solution within a semipermeable membrane. The osmotic pressure developed when the artificial cell is placed within a \(0.05 \, \text{M}\) solution of NaCl at 300 K is ______ \( \times 10^{-1} \, \text{bar} \). (Nearest Integer)
Given: \(R = 0.083 \, \text{L bar mol}^{-1} \text{K}^{-1}\)
Assume complete dissociation of NaCl.

Updated On: Nov 29, 2024
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Correct Answer: 25

Solution and Explanation

For NaCl dissociation:
\[ \text{NaCl} \rightarrow \text{Na}^+ + \text{Cl}^- \]
Concentration of NaCl = 0.05 M.
Effective concentration (\(C_1\)) = 0.05 M + 0.05 M = 0.1 M. 
Glucose concentration (\(C_2\)) = 0.2 M.
The osmotic pressure:
\[ \pi = (C_2 - C_1)RT \]
Explanation 87
Substituting:
\[ \pi = (0.2 - 0.1) \times 0.083 \times 300 = 24.9 \times 10^{-1} \, \text{bar} \]
Nearest integer = 25 bar.

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