Biot-Savart's law relates the magnetic field produced by a current-carrying wire. Ampere's circuital law is an alternative form of the Biot-Savart law, and it provides a relationship between the magnetic field and the electric current in a circuit.
The integral form of Ampere's law is: \[ \oint \vec{B} \cdot d\vec{l} = \mu_0 I_{{enc}} \] where:
- \( \vec{B} \) is the magnetic field,
- \( d\vec{l} \) is the differential length element of the closed loop,
- \( I_{{enc}} \) is the enclosed current,
- \( \mu_0 \) is the permeability of free space.
Hence, the correct answer is (D).
Two long parallel wires X and Y, separated by a distance of 6 cm, carry currents of 5 A and 4 A, respectively, in opposite directions as shown in the figure. Magnitude of the resultant magnetic field at point P at a distance of 4 cm from wire Y is \( 3 \times 10^{-5} \) T. The value of \( x \), which represents the distance of point P from wire X, is ______ cm. (Take permeability of free space as \( \mu_0 = 4\pi \times 10^{-7} \) SI units.) 
A particle of charge $ q $, mass $ m $, and kinetic energy $ E $ enters in a magnetic field perpendicular to its velocity and undergoes a circular arc of radius $ r $. Which of the following curves represents the variation of $ r $ with $ E $?
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : If oxygen ion (O\(^{-2}\)) and Hydrogen ion (H\(^{+}\)) enter normal to the magnetic field with equal momentum, then the path of O\(^{-2}\) ion has a smaller curvature than that of H\(^{+}\).
Reason R : A proton with same linear momentum as an electron will form a path of smaller radius of curvature on entering a uniform magnetic field perpendicularly.
In the light of the above statements, choose the correct answer from the options given below