The steam volatile compounds among the following are:

To solve this problem, we need to understand the relationship between steam volatility, intermolecular forces (especially hydrogen bonding), and molecular structure.
1. Understanding Steam Volatility:
Steam volatile compounds can be distilled using steam distillation, meaning they vaporize readily in the presence of steam. This is favored by lower boiling points and weaker intermolecular forces.
2. The Role of Hydrogen Bonding:
Intramolecular hydrogen bonds (within a molecule) increase volatility because they reduce the molecule's ability to form strong intermolecular interactions. Intermolecular hydrogen bonds (between molecules) decrease volatility by increasing the strength of the interactions between molecules.
3. Identifying Key Factors:
The key factor determining steam volatility in this context is the presence of intramolecular hydrogen bonds. Molecules with these bonds are more volatile due to reduced intermolecular attraction.
4. Conclusion:
Molecules with intramolecular hydrogen bonds are more likely to be steam volatile.
Final Answer:
Molecules with intramolecular hydrogen bonds are more likely to be steam volatile are A and B
The structure of the major product formed in the following reaction is:

Consider the following reaction occurring in the blast furnace. \[ {Fe}_3{O}_4(s) + 4{CO}(g) \rightarrow 3{Fe}(l) + 4{CO}_2(g) \] ‘x’ kg of iron is produced when \(2.32 \times 10^3\) kg \(Fe_3O_4\) and \(2.8 \times 10^2 \) kg CO are brought together in the furnace.
The value of ‘x’ is __________ (nearest integer).
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]
X g of benzoic acid on reaction with aqueous \(NaHCO_3\) release \(CO_2\) that occupied 11.2 L volume at STP. X is ________ g.
Standard entropies of \(X_2\), \(Y_2\) and \(XY_5\) are 70, 50, and 110 J \(K^{-1}\) mol\(^{-1}\) respectively. The temperature in Kelvin at which the reaction \[ \frac{1}{2} X_2 + \frac{5}{2} Y_2 \rightarrow XY_5 \quad \Delta H = -35 \, {kJ mol}^{-1} \] will be at equilibrium is (nearest integer):