Step 1: Analyze each compound to identify tetrahedral geometry.
1. \([Co(CN)_4]^{4-}\): CN is a strong ligand. Due to pairing, it undergoes \(sp^3\) hybridization, forming a tetrahedral structure.
2. \([Co(CO)_3(NO)]\): This forms a trigonal planar geometry due to the coordination environment.
3. \(XeF_4\): Square planar geometry, not tetrahedral.
4. \([PCl_4]^+\): Tetrahedral geometry due to \(sp^3\) hybridization.
5. \([PdCl_4]^{2-}\): Square planar geometry.
6. \([ICl_4]^-\): Square planar geometry.
7. \([Cu(CN)_4]^{3-}\): CN being a strong ligand leads to \(sp^3\) hybridization, hence tetrahedral.
8. \(P_4\): Tetrahedral geometry due to its molecular structure.
Step 2: Count the species with tetrahedral geometry.
Tetrahedral species: \([Co(CN)_4]^{4-}\), \([PCl_4]^+\), \([Cu(CN)_4]^{3-}\), and \(P_4\).
Step 3: Final answer. The total number of tetrahedral species is: \[ 5 \]
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]