Ammonia and oxygen react at high temperature as in reaction,
4HN3(g) + 5O2(g) → 4NO(g) + 6H2O(g)
If rate of formation of NO is 3.6 x 10–3 mol L–1 .sec–1 . Calculate the rate of formation of water.
Ammonia and oxygen react at high temperature as in reaction,
4HN3(g) + 5O2(g) → 4NO(g) + 6H2O(g)
If rate of formation of NO is 3.6 x 10–3 mol L–1 .sec–1 . Calculate the rate of formation of water.
6.0 x 10–3 mol L–1 sec–1
3.6 x 10–3 mol L–1 sec–1
1.8 x 10–3 mol L–1 sec–1
5.4 x 10–3 mol L–1 sec–1
The Correct Option is D
Solution and Explanation
From the balanced equation, we can see that the stoichiometric ratio between NO and H2O is 4:6 or 2:3. This means that for every 4 moles of NO formed, 6 moles of H2O will be formed.
Given that the rate of formation of NO is 3.6x10-3 mol L-1 sec-1
We can calculate the rate of formation of water as follows:
Rate of formation of H2O = (3.6x10-3 mol L-1 sec-1) x \(\frac {6}{4}\) = 5.4 x 10-3 mol L-1 sec-1
Therefore, the rate of formation of water is 5.4 x 10-3 mol L-1 sec-1, which corresponds to option (D).
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Concepts Used:
Rate of a Chemical Reaction
The rate of a chemical reaction is defined as the change in concentration of any one of the reactants or products per unit time.
Consider the reaction A → B,
Rate of the reaction is given by,
Rate = −d[A]/ dt=+d[B]/ dt
Where, [A] → concentration of reactant A
[B] → concentration of product B
(-) A negative sign indicates a decrease in the concentration of A with time.
(+) A positive sign indicates an increase in the concentration of B with time.
Factors Determining the Rate of a Reaction:
There are certain factors that determine the rate of a reaction:
- Temperature
- Catalyst
- Reactant Concentration
- Chemical nature of Reactant
- Reactant Subdivision rate