According to recent research, air turbulence has increased in various regions around the world due to climate change. Turbulence makes flights bumpy and often delays the flights.
Assume that an airplane observes severe turbulence, moderate turbulence or light turbulence with equal probabilities. Further, the chance of an airplane reaching late to the destination are 55\%, 37\% and 17\% due to severe, moderate and light turbulence respectively.
On the basis of the above information, answer the following questions:
Find the probability that an airplane reached its destination late. If the airplane reached its destination late, find the probability that it was due to moderate turbulence.
Step 1: Given Information. Turbulence can be severe, moderate, or light, each occurring with equal probabilities: \[ P(\text{Severe}) = P(\text{Moderate}) = P(\text{Light}) = \frac{1}{3}. \] The probability of an airplane reaching late due to: \[ P(\text{Late}|\text{Severe}) = 0.55, \quad P(\text{Late}|\text{Moderate}) = 0.37, \quad P(\text{Late}|\text{Light}) = 0.17. \].
Step 2: Find the probability that an airplane reached its destination late. Using the law of total probability: \[ P(\text{Late}) = P(\text{Late}|\text{Severe})P(\text{Severe}) + P(\text{Late}|\text{Moderate})P(\text{Moderate}) + P(\text{Late}|\text{Light})P(\text{Light}) \] Substituting the values: \[ P(\text{Late}) = (0.55 \cdot \frac{1}{3}) + (0.37 \cdot \frac{1}{3}) + (0.17 \cdot \frac{1}{3}) \] Simplifying: \[ P(\text{Late}) = \frac{0.55 + 0.37 + 0.17}{3} = \frac{1.09}{3} = 0.3633. \]
Step 3: Find the probability that it was due to moderate turbulence. Using Bayes' theorem: \[ P(\text{Moderate}|\text{Late}) = \frac{P(\text{Late}|\text{Moderate})P(\text{Moderate})}{P(\text{Late})} \] Substituting the values: \[ P(\text{Moderate}|\text{Late}) = \frac{(0.37 \cdot \frac{1}{3})}{0.3633} \] \[ P(\text{Moderate}|\text{Late}) = \frac{0.37}{3 \cdot 0.3633} = \frac{0.37}{1.09} = 0.3394. \]
Final Answers: The probability that an airplane reached its destination late is: \[ P(\text{Late}) = 0.3633. \] The probability that the airplane was late due to moderate turbulence is: \[ P(\text{Moderate}|\text{Late}) = 0.3394. \]
A gardener wanted to plant vegetables in his garden. Hence he bought 10 seeds of brinjal plant, 12 seeds of cabbage plant, and 8 seeds of radish plant. The shopkeeper assured him of germination probabilities of brinjal, cabbage, and radish to be 25%, 35%, and 40% respectively. But before he could plant the seeds, they got mixed up in the bag and he had to sow them randomly.
Given three identical bags each containing 10 balls, whose colours are as follows:
| Bag I | 3 Red | 2 Blue | 5 Green |
| Bag II | 4 Red | 3 Blue | 3 Green |
| Bag III | 5 Red | 1 Blue | 4 Green |
A person chooses a bag at random and takes out a ball. If the ball is Red, the probability that it is from Bag I is $ p $ and if the ball is Green, the probability that it is from Bag III is $ q $, then the value of $ \frac{1}{p} + \frac{1}{q} $ is:
A battery of emf \( E \) and internal resistance \( r \) is connected to a rheostat. When a current of 2A is drawn from the battery, the potential difference across the rheostat is 5V. The potential difference becomes 4V when a current of 4A is drawn from the battery. Calculate the value of \( E \) and \( r \).
If \(\begin{vmatrix} 2x & 3 \\ x & -8 \\ \end{vmatrix} = 0\), then the value of \(x\) is: