The probability that a student passes only in Mathematics is \(\frac{1}{3}\).The probability that the student passes only in English is \(\frac{4}{9}\).The probability that the student passes in both of these subjects \(\frac{1}{6}\).The probability that the student will pass in at least one of these two subjects is
- \( \frac{17}{18}\)
- \( \frac{11}{18}\)
- \( \frac{14}{18}\)
- \( \frac{1}{18}\)
The Correct Option is A
Solution and Explanation
Top Questions on Conditional Probability
A gardener wanted to plant vegetables in his garden. Hence he bought 10 seeds of brinjal plant, 12 seeds of cabbage plant, and 8 seeds of radish plant. The shopkeeper assured him of germination probabilities of brinjal, cabbage, and radish to be 25%, 35%, and 40% respectively. But before he could plant the seeds, they got mixed up in the bag and he had to sow them randomly.
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\(\text{Match List-I with List-II:}\)
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