The probability that a student passes only in Mathematics is \(\frac{1}{3}\).The probability that the student passes only in English is \(\frac{4}{9}\).The probability that the student passes in both of these subjects \(\frac{1}{6}\).The probability that the student will pass in at least one of these two subjects is
- \( \frac{17}{18}\)
- \( \frac{11}{18}\)
- \( \frac{14}{18}\)
- \( \frac{1}{18}\)
The Correct Option is A
Solution and Explanation
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3. \( R<T \)
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