The compound has a hydroxyl group (-OH) attached to the first carbon in the cyclohexene
ring, and the double bond is at the second carbon. According to IUPAC nomenclature: -
The base name ”Cyclohex” comes from the cyclohexane ring. - The double bond is between
positions 2 and 3, so we have ”Cyclohex-2-en”. - The hydroxyl group is at position 1, so the
name ends with ”1-ol”.
Thus, the correct IUPAC name is ”Cyclohex-2-en-1-ol”.
The Correct Answer is: Cyclohex-2-en-1-ol
The IUPAC name of the following compound is:
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: