



Relation Between Height and Depth for Equal Acceleration Due to Gravity
The acceleration due to gravity at a height h above the Earth's surface is given by:
\[ g_h = g \left(1 - \frac{2h}{R}\right) \]
The acceleration due to gravity at a depth d below the Earth's surface is given by:
\[ g_d = g \left(1 - \frac{d}{R}\right) \]
To find the relation between height and depth when both give the same gravity, we equate \( g_h = g_d \):
\[ g \left(1 - \frac{2h}{R}\right) = g \left(1 - \frac{d}{R}\right) \]
Canceling \( g \) on both sides:
\[ 1 - \frac{2h}{R} = 1 - \frac{d}{R} \]
Simplifying:
\[ \frac{2h}{R} = \frac{d}{R} \Rightarrow 2h = d \]
Conclusion: When the acceleration due to gravity is the same at a height h and a depth d, then the relation is \( d = 2h \).
The correct answer is option (C):

A particle of mass \(m\) falls from rest through a resistive medium having resistive force \(F=-kv\), where \(v\) is the velocity of the particle and \(k\) is a constant. Which of the following graphs represents velocity \(v\) versus time \(t\)? 


Which of the following statement(s) is/are correct about the given compound?

In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.
