Relation Between Height and Depth for Equal Acceleration Due to Gravity
The acceleration due to gravity at a height h above the Earth's surface is given by:
\[ g_h = g \left(1 - \frac{2h}{R}\right) \]
The acceleration due to gravity at a depth d below the Earth's surface is given by:
\[ g_d = g \left(1 - \frac{d}{R}\right) \]
To find the relation between height and depth when both give the same gravity, we equate \( g_h = g_d \):
\[ g \left(1 - \frac{2h}{R}\right) = g \left(1 - \frac{d}{R}\right) \]
Canceling \( g \) on both sides:
\[ 1 - \frac{2h}{R} = 1 - \frac{d}{R} \]
Simplifying:
\[ \frac{2h}{R} = \frac{d}{R} \Rightarrow 2h = d \]
Conclusion: When the acceleration due to gravity is the same at a height h and a depth d, then the relation is \( d = 2h \).
The correct answer is option (C):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of:
In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.