The increase in length of a wire when subjected to a force is given by:
where:
- is the original length of the wire,
- is the cross-sectional area of the wire,
- is Young’s modulus of the material of the wire.
If both the force and the radius are reduced to half, let’s see how changes.
Step 1: New Force:
Step 2: New Radius and Area:
Since the radius is reduced to half:
The new cross-sectional area is:
Step 3: New Increase in Length :
Substituting the new values of and :
Thus, the increase in length will become 2 times the original increase in length.
The Correct Answer is: 2 Times
Let be the solution of the differential equation
such that , then is equal to:
Find the IUPAC name of the compound.
If , then is: 32