Question:
A wire bent into circular loop A carries current I. The same wire is bent into loop B with two turns, same current. Find the ratio of magnetic fields at the centers of A to B.
A wire bent into circular loop A carries current I. The same wire is bent into loop B with two turns, same current. Find the ratio of magnetic fields at the centers of A to B.
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Consider the relationship between circumference and radius with the number of turns.
Updated On: Feb 16, 2025
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The Correct Option is D
Solution and Explanation
B_A = µ₀I/(2r_A). B_B = µ₀I/r_B (doubled for two turns). Since the wire length is constant, 2πr_A = 4πr_B, so r_B = r_A/2. Thus, B_A/B_B = (1/4).
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