The speed \( v \) of a wave is related to its frequency \( f \) and wavelength \( \lambda \) by the equation: \[ v = f \times \lambda \] where:
- \( f = 600 \, {Hz} \) is the frequency of the wave,
- \( \lambda = 0.5 \, {m} \) is the wavelength.
Substituting the values: \[ v = 600 \times 0.5 = 300 \, {m/s} \] Now, to find the time \( t \) it takes for the wave to travel a distance of 200 m, we use the equation: \[ v = \frac{{distance}}{{time}} \quad \Rightarrow \quad t = \frac{{distance}}{v} \] Substitute the values: \[ t = \frac{200}{300} = 0.67 \, {s} \] Thus, the time taken for the wave to travel 200 m is \( 0.67 \, {s} \).
Therefore, the correct answer is option (B), 0.67 s.
Let \( f(x) = \frac{x^2 + 40}{7x} \), \( x \neq 0 \), \( x \in [4,5] \). The value of \( c \) in \( [4,5] \) at which \( f'(c) = -\frac{1}{7} \) is equal to:
The general solution of the differential equation \( \frac{dy}{dx} = xy - 2x - 2y + 4 \) is:
The minimum value of the function \( f(x) = x^4 - 4x - 5 \), where \( x \in \mathbb{R} \), is:
The critical points of the function \( f(x) = (x-3)^3(x+2)^2 \) are:
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: