Question:

A triangle is formed by $X$-axis, $Y$-axis and the line $3 x+4 y=60$ Then the number of points $P ( n , b )$ which lie strictly inside the triangle, where a is an integer and $b$ is a multiple of a, is ____

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When solving geometry problems with constraints, carefully analyze integer solutions and relationships between coordinates

Updated On: Jan 9, 2025
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Correct Answer: 31

Approach Solution - 1

The intercepts of the line are (20,0) and (0,15). Compute the points inside the triangle satisfying b = ka. The total is: 31points.

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Approach Solution -2

The correct answer is 31
Triangle on a Graph

\((1,1)(1,2)−(1,14)⇒14 pts.\)

If \(x=2\), \(y=\frac{27}{2} = 13.5\)

\((2,2)(2,4)…(2,12)⇒6 pts.\)

If \(x=3\), \(y=\frac{51}{4} = 12.75\)

\((3,3)(3,6)−(3,12)⇒4 pts.\)

If \(x=4\), \(y=12\)

\((4,4)(4,8)⇒2 pts.\)

If \(x=5\), \(y=\frac{45}{4} = 11.25\)

\((5,5),(5,10)⇒2 pts.\)

If \(x=6\), \(y=\frac{21}{2} = 10.5\)

\((6,6)⇒1pt\)

If \(x=7\), \(y=\frac{39}{4} = 9.75\)

(7,7)⇒1pt

If \(x=8\), \(y=9\)

\((8,8)⇒1pt\)

If \(x=9\) \(y=\frac{33}{4}= 8.25\)\(\Rightarrow\) no pt.

Total = 31 pts.

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Concepts Used:

Quadratic Equations

A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers

Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.

The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)

Two important points to keep in mind are:

  • A polynomial equation has at least one root.
  • A polynomial equation of degree ‘n’ has ‘n’ roots.

Read More: Nature of Roots of Quadratic Equation

There are basically four methods of solving quadratic equations. They are:

  1. Factoring
  2. Completing the square
  3. Using Quadratic Formula
  4. Taking the square root