Question:

A student skates up a ramp that makes an angle $30^{\circ}$ with the horizontal. He/she starts (as shown in the figure) at the bottom of the ramp with speed $v_{0}$ and wants to turn around over a semicircular path $xyz$ of radius $R$ during which he/she reaches a maximum height $h$ (at point $y$) from the ground as shown in the figure. Assume that the energy loss is negligible and the force required for this turn at the highest point is provided by his/her weight only. Then ( $g$ is the acceleration due to gravity)
A student skates up a ramp that makes an angle

Updated On: Apr 25, 2024
  • $v _{0}^{2}-2 gh =\frac{1}{2} gR$
  • $v _{0}^{2}-2 gh =\frac{\sqrt{3}}{2} gR$
  • the centripetal force required at points $x$ and $z$ is zero
  • the centripetal force required is maximum at points $x$ and $z$
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The Correct Option is A, D

Solution and Explanation

(A) $v _{0}^{2}-2 gh =\frac{1}{2} gR$
(D) the centripetal force required is maximum at points $x$ and $z$
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