A student is asked to answer 10 out of 13 questions in an examination such that he must answer at least four questions from the first five questions. Then the total number of possible choices available to him is
186
176
286
196
The correct option is (D) 196.
(i) Choosing 4 out of the first five questions and 6 out of the remaining 8 questions. Therefore, the number of choices in this case is given by 5C4×8C6=5C1×8C2=5×8×1×27=140.
(ii) Choosing 5 out of the first five questions and 5 out of the remaining 8 questions. This leads to 5C5×8C5=1×8C3=5×8×1×2×37=56.
Hence, the total number of choices is 140+56=196140+56=196.
The value of 49C3 + 48C3 + 47C3 + 46C3 + 45C3 + 45C4 is:
The method of forming subsets by selecting data from a larger set in a way that the selection order does not matter is called the combination.
But you are only allowed to pick three.
It is used for a group of data (where the order of data doesn’t matter).