Question:

A spherical shell is shown in figure. What is the electric field inside the shell?

Updated On: Jul 5, 2022
  • $\frac{1}{4\pi\varepsilon_{0}} \frac{q}{R^{2}}$
  • $\frac{1}{4\pi\varepsilon_{0}} \frac{q}{r^{2}}$
  • Zero
  • $\frac{1}{4\pi\varepsilon_{0}} \frac{q}{(r+R)^{2}}$
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The Correct Option is C

Solution and Explanation

Inside the spherical shell the electric field is zero as there is no charged particle reside inside the shell.
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Concepts Used:

Gauss Law

Gauss law states that the total amount of electric flux passing through any closed surface is directly proportional to the enclosed electric charge.

Gauss Law:

According to the Gauss law, the total flux linked with a closed surface is 1/ε0 times the charge enclosed by the closed surface.

For example, a point charge q is placed inside a cube of edge ‘a’. Now as per Gauss law, the flux through each face of the cube is q/6ε0.

Gauss Law Formula:

As per the Gauss theorem, the total charge enclosed in a closed surface is proportional to the total flux enclosed by the surface. Therefore, if ϕ is total flux and ϵ0 is electric constant, the total electric charge Q enclosed by the surface is;

Q = ϕ ϵ0

The Gauss law formula is expressed by;

ϕ = Q/ϵ0

Where,

Q = total charge within the given surface,

ε0 = the electric constant.