Comprehension

A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux. The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment $m$ is brought along the axis of this loop from infinity to a point at distance $r(>>$ a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.
The magnitude of magnetic field of a dipole $m$, at a point on its axis at distance $r$, is $\frac{\mu_{0}}{2 \pi} \frac{ m }{ r ^{3}}$, where $\mu_{0}$ is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, $m _{1}$ and $m _{2}$, separated by a distance $r$ on the common axis, with their north poles facing each other, is $\frac{ km _{1} m _{2}}{ r ^{4}}$, where $k$ is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.
special metal S conducts electricity

Question: 1

When the dipole m is placed at a distance r from the center of the loop (as shown in the figure), the current induced in the loop will be proportional to

Updated On: May 28, 2024
  • $\frac{m }{ r ^{3}}$

  • \(\frac{m^2}{r^2}\)

  • \(\frac{m}{r^2}\)

  • \(\frac{m^2}{r}\)

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The Correct Option is A

Solution and Explanation

The correct answer is (A) :\(\frac{m }{ r ^{3}}\)

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Question: 2

The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional to?

Updated On: May 24, 2024
  • \(\frac{m}{r^5}\)

  • \(\frac{m^2}{r^5}\)

  • \(\frac{m^2}{r^6}\)

  • \(\frac{m^2}{r^7}\)

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The Correct Option is C

Solution and Explanation

The correct answer is (C): \(\frac{m^2}{r^6}\)

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