Given:
- Solution (I): Mass of sugar = 200 g, sugar percentage = 25%
- Solution (II): Mass of sugar = 500 g, sugar percentage = 40%
Mass of sugar in solution (I):
\[
\frac{25}{100} \times 200 = 50 \, \text{g}
\]
Mass of sugar in solution (II):
\[
\frac{40}{100} \times 500 = 200 \, \text{g}
\]
Total mass of solution = 200 + 500 = 700 g
Total mass of sugar = 50 + 200 = 250 g
Now, the final percentage of sugar is:
\[
\frac{250}{700} \times 100 = 35.71 \approx 36
\]
Thus, the mass percentage of sugar is 36%. The correct answer is (36).