The molar mass of water (\( \text{H}_2\text{O} \)) is 18 g/mol. Since we have 1 mole of water:
\[ \text{Mass of solvent} = 1 \, \text{mol} \times 18 \, \text{g/mol} = 18 \, \text{g}. \]
The total mass of the solution is the sum of the mass of the solute and the mass of the solvent:
\[ \text{Total mass} = \text{Mass of solute} + \text{Mass of solvent} = 2 \, \text{g} + 18 \, \text{g} = 20 \, \text{g}. \]
The mass percent of \( X \) is given by:
\[ \% \text{mass of } X = \frac{\text{Mass of } X}{\text{Total mass}} \times 100 = \frac{2 \, \text{g}}{20 \, \text{g}} \times 100 = 10\%. \]
The mass percent of \( X \) in the solution is 10%.
0.1 mole of compound S will weigh ...... g, (given the molar mass in g mol\(^{-1}\) C = 12, H = 1, O = 16) 
Among $ 10^{-10} $ g (each) of the following elements, which one will have the highest number of atoms?
Element : Pb, Po, Pr and Pt
If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
The output of the circuit is low (zero) for:

(A) \( X = 0, Y = 0 \)
(B) \( X = 0, Y = 1 \)
(C) \( X = 1, Y = 0 \)
(D) \( X = 1, Y = 1 \)
Choose the correct answer from the options given below:
The metal ions that have the calculated spin only magnetic moment value of 4.9 B.M. are
A. $ Cr^{2+} $
B. $ Fe^{2+} $
C. $ Fe^{3+} $
D. $ Co^{2+} $
E. $ Mn^{2+} $
Choose the correct answer from the options given below
Which of the following circuits has the same output as that of the given circuit?
