A solid cylinder length is suspended symmetrically through two massless strings, as shown in the figure. The distance from the initial rest position, the cylinder should be unbinding the strings to achieve a speed of 4 m/s, is ______ cm. (Take g = 10 m/s2).
The correct answer is 120
\(α = \frac{(mg)(r)}{\frac{3}{2}mr^2} = \frac{2g}{3r}\)
\(⇒ a = \frac{2g}{3}\)
\(⇒ v^2 = 2as\)
\(16 = \frac{40}{3}×s\)
⇒ s = 0.3×4
= 120cm
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
Rotational motion can be defined as the motion of an object around a circular path, in a fixed orbit.
The wheel or rotor of a motor, which appears in rotation motion problems, is a common example of the rotational motion of a rigid body.
Other examples: