Question

A shear stress $ \tau $ acts tangentially to the upper surface of a block and causes a small deformation $ \Delta w $ as shown. The shear strain is calculated by

• A. \( \frac{\Delta w}{w} \)
• B. \( \frac{\Delta w}{h} \)
• C. \( \frac{2 \Delta w}{w} \)
• D. \( \frac{2 \Delta w h}{h} \)

Hint:

Shear strain = lateral displacement / height of block.

Answer 1

The Correct Option is B

Shear strain \( \gamma = \frac{\text{deformation}}{\text{height}} = \frac{\Delta w}{h} \).