The resolving power (\(P\)) of a microscope is given by: \[ P = \frac{2 \mu \sin \theta}{1.22 \lambda}, \] where: \(\mu\) is the refractive index of the medium, \item \(\lambda\) is the wavelength of light.
To improve resolving power: Increasing \(\mu\) (refractive index) improves \(P\), Decreasing \(\lambda\) also increases \(P\).
The refractive index of glass is 1.6 and the speed of light in glass will be ……… . The speed of light in vacuum is \( 3.0 \times 10^8 \) ms\(^{-1}\).
Consider a refracting telescope whose objective has a focal length of 1m and the eyepiece a focal length of 1cm, then the magnifying power of this telescope will be ……..
For the reaction \( A \rightarrow \) products,
The reaction was started with 2.5 mol L\(^{-1}\) of A.
Consider the following electrochemical cell at standard condition. \[ \text{Au(s) | QH}_2\text{ | QH}_X(0.01 M) \, \text{| Ag(1M) | Ag(s) } \, E_{\text{cell}} = +0.4V \] The couple QH/Q represents quinhydrone electrode, the half cell reaction is given below: \[ \text{QH}_2 \rightarrow \text{Q} + 2e^- + 2H^+ \, E^\circ_{\text{QH}/\text{Q}} = +0.7V \]
Consider the following compound (X):
The most stable and least stable carbon radicals, respectively, produced by homolytic cleavage of corresponding C - H bond are:
A device that processes light waves (or photons), either to enhance an image for viewing or to analyze and determine its characteristic properties is called an optical instrument (or "optic" for short).