Question:

A sample of a metal oxide has formula $M _{0.83} O _{1.00}$ The metal $M$ can exist in two oxidation states $+2$ and $+3$ In the sample of $M _{0.83} O _{1.00}$, the percentage of metal ions existing in $+2$ oxidation state is___$ \%$ (nearest integer)

Updated On: Sep 30, 2024
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Correct Answer: 59

Approach Solution - 1

A sample of a metal oxide
2x+3(0.83−x)=2 
x=0.49 
%M2+=0.830.49​×100 
=59%
So , the correct answer is 59.
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Approach Solution -2

The accurate response is 59%.
By solving the equation \(2x+3(0.83−x)=2\),
we obtain the value of x as 0.49.
Therefore, the percentage of metal ions present in the +2 oxidation state
\((\% M^{2+})\) can be calculated as \(\frac{(0.83-0.49)}{0.83} \times 100\),
which simplifies to \(59\%\).
So, the correct answer is 59.

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Some Basic Concepts of Chemistry

Chemistry is a vast subject and for understanding its significance we can take help of following points:

  • Chemistry plays an important role in understanding various subjects like physics, geology and biology.
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Classification of Matter

There are two ways of classifying the matter:

(A) Physical Classification:

Matter can exist in three physical states:

  1. Solids - have definite volume and definite shape
  2. Liquids - have definite volume but not definite shape.
  3. Gases - have neither definite volume nor definite shape.

(B) Chemical Classification:

Based upon the composition, matter can be divided into two main types:

  1. Pure Substances are defined as a single substance (or matter) which cannot be separated by simple physical methods. Pure substances can be further classified as (i) Elements (ii) Compounds
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