Let's analyze the seating arrangement and identify the initial position of Bashir:
Thus, Bashir initially occupied chair 4. |
Davies occupies Chair 2 after Turn 1. Since he does not move in Turn 1, he must already be in Chair 2 initially.
He must have empty chairs on both sides initially; hence Chairs 1 and 3 were empty at the start.
\[ D \text{ at } 2,\quad \text{so Chairs } 1 \text{ and } 3 \text{ are empty.} \]
Chhavi occupies Chair 7 after Turn 2. She does not move until Turn 3; therefore, she must have been at Chair 7 initially.
\[ C \text{ at } 7. \]
Aslam and Chhavi are adjacent initially. The chairs adjacent to 7 are 6 and 1. Since Chair 1 must be empty, Aslam must be at Chair 6.
\[ A \text{ at } 6. \]
So far:
\[ D(2),\ A(6),\ C(7),\ \text{empty: } 1,3,\text{ and two of } \{4,5\}. \]
Remaining chairs: 4 and 5. Bashir must have empty chairs on both sides initially.
Neighbors: 4 and 6. Chair 6 is occupied → invalid.
Neighbors: 3 and 5. Both are empty → valid.
\[ B \text{ at } 4. \]
Initial configuration:
\[ A(6),\ B(4),\ C(7),\ D(2). \]
Empty chairs: 1, 3, 5.
From 6, the first empty clockwise is 1 → Aslam moves to 1.
\[ A(1), D(2), B(4), C(7) \]
Nearest empty counterclockwise is 3 → Bashir moves to 3.
Occupied chairs are \(7, 1, 2, 3\): a block of four adjacent chairs, satisfying the condition.
Bashir initially occupied \(\boxed{4}\).
To solve the problem, we will carefully follow the details provided in the comprehension building block, using the rules and movements described:
Therefore, the correct answer is:
No one
Aslam moves first from Chair 6. To allow the adjacency of all four friends at the end of Turn 2 (a required condition), Aslam must move to Chair 1.
\[ A(1),\ D(2),\ B(4),\ C(7) \]
Bashir moves from Chair 4. To make all four friends adjacent at the end of Turn 2, Bashir must move to the empty Chair 3.
\[ A(1),\ D(2),\ B(3),\ C(7) \]
The chairs \(7,1,2,3\) form a consecutive block — satisfying the condition.
Chhavi is at Chair 7. Empty chairs are 4, 5, and 6.
If Chhavi moved to Chair 4, the occupied chairs would be \(1,2,3,4\): This forms another block of four adjacent friends.
But the problem states they are adjacent only at the end of Turn 2 and Turn 6. Thus Chhavi cannot move to Chair 4.
She must move in the other direction, reaching Chair 6 (the first empty chair counterclockwise).
\[ A(1),\ D(2),\ B(3),\ C(6) \]
Chair 4 remains empty at the end of Turn 3.
\[ \boxed{\text{No one sits on Chair 4}} \]
To determine which chairs are occupied at the end of Turn 6, let's analyze the problem step by step based on the information given:
From the previous analysis:
\[ A(1),\ D(2),\ B(3),\ C(6) \]
Chairs 4, 5, and 7 are empty.
Davies is currently at Chair 2. We are told that Davies must be at Chair 4 after Turn 5. Since Davies does not move in Turn 5, he must move to Chair 4 now in Turn 4.
\[ A(1),\ B(3),\ D(4),\ C(6) \]
Aslam is at Chair 1. We know that at the end of Turn 6, all four friends must again occupy adjacent chairs. To make that possible, Aslam should move from Chair 1 to Chair 7 (the first empty chair clockwise or counterclockwise chosen suitably).
\[ B(3),\ D(4),\ C(6),\ A(7) \]
Empty chair is 5.
Bashir is at Chair 3. The empty chair is 5. Moving from 3 to 5 (via the first empty in a suitable direction) gives:
\[ D(4),\ B(5),\ C(6),\ A(7) \]
Now the occupied chairs are \(4, 5, 6, 7\) — a block of four adjacent chairs, satisfying the condition that they are all adjacent at the end of Turn 6.
At the end of Turn 6, the occupied chairs are:
\[ \boxed{4, 5, 6, \text{ and } 7} \]
Which of the following BEST describes the friends sitting on chairs adjacent to the one occupied by Bashir at the end of Turn 7?
To solve this question about seating arrangements at the end of different turns, let's follow the given data and rules systematically.
Understanding Initial Conditions and Moves:
Let's analyze this further based on the given conditions:
Step-by-step seating position after each turn:
As a result, at the end of Turn 7, Bashir is not adjacent to Chhavi anymore but possibly remains alongside due to the arrangement, where Davies is the only neighbor of Bashir.
Conclusion: Thus, the friend sitting adjacent to Bashir at the end of Turn 7 is \(Davies\) only, which corresponds to option (b).
From the previous turns, we know that at the end of Turn 6 the configuration was:
\[ D(4),\ B(5),\ C(6),\ A(7) \] & nbsp;
All four are on adjacent chairs \(4, 5, 6, 7\).
At the start of Turn 7:
\[ B(5),\ D(4),\ C(6),\ A(7) \]
Chhavi is at Chair 6. She must move in Turn 7 to the first empty chair in either clockwise or counterclockwise direction.
At this moment, the only empty chairs are 1, 2, and 3. Wherever Chhavi moves, she vacates Chair 6, so after her move:
Bashir is at Chair 5. The chairs adjacent to Chair 5 are:
After Turn 7:
So, the only friend adjacent to Bashir is Davies.
At the end of Turn 7, only Davies sits adjacent to Bashir.
\[ \boxed{\text{Davies only}} \]
At InnovateX, six employees, Asha, Bunty, Chintu, Dolly, Eklavya, and Falguni, were split into two groups of three each: Elite led by Manager Kuku, and Novice led by Manager Lalu. At the end of each quarter, Kuku and Lalu handed out ratings to all members in their respective groups. In each group, each employee received a distinct integer rating from 1 to 3. & nbsp;
The score for an employee at the end of a quarter is defined as their cumulative rating from the beginning of the year. At the end of each quarter the employee in Novice with the highest score was promoted to Elite, and the employee in Elite with the minimum score was demoted to Novice. If there was a tie in scores, the employee with a higher rating in the latest quarter was ranked higher.
1. Asha, Bunty, and Chintu were in Elite at the beginning of Quarter 1. All of them were in Novice at the beginning of Quarter 4.
2. Dolly and Falguni were the only employees who got the same rating across all the quarters.
3. The following is known about ratings given by Lalu (Novice manager):
– Bunty received a rating of 1 in Quarter 2. & nbsp;
– Asha and Dolly received ratings of 1 and 2, respectively, in Quarter 3.
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: