Step 1: Understanding the relation.
The relation is defined as $a = b - 1$ and $b > 4$. This means for every element $b > 4$, we will find the corresponding $a$ such that $a = b - 1$.
Step 2: Check each option.
- (A) $(2, 4)$: For $a = 2$, $b = 2 + 1 = 3$, but $b > 4$ is not satisfied. Hence, $(2, 4)$ is incorrect.
- (B) $(4, 5)$: For $a = 4$, $b = 4 + 1 = 5$, and $b > 4$ is satisfied. Hence, $(4, 5)$ is correct.
- (C) $(4, 6)$: For $a = 4$, $b = 4 + 1 = 5$, but $b = 6$ does not match the condition for $b = 5$ when $a = 4$. Hence, $(4, 6)$ is incorrect.
- (D) $(3, 5)$: For $a = 3$, $b = 3 + 1 = 4$, but $b > 4$ is not satisfied. Hence, $(3, 5)$ is incorrect.
Step 3: Conclusion.
The correct answer is (B) $(4, 5)$, as it satisfies both conditions $a = b - 1$ and $b > 4$.
Let $R$ be a relation defined on the set $\{1,2,3,4\times\{1,2,3,4\}$ by \[ R=\{((a,b),(c,d)) : 2a+3b=3c+4d\} \] Then the number of elements in $R$ is
Let \(M = \{1, 2, 3, ....., 16\}\), if a relation R defined on set M such that R = \((x, y) : 4y = 5x – 3, x, y (\in) M\). How many elements should be added to R to make it symmetric.