The correct answer is 16
As slope of line joining (1, 2) and (3, 6) is 2 given diameter is parallel to side
Hence, \(a = \sqrt{(3−1)^2+(6−2)^2}\)
\(= \sqrt{20}\)
Thereafter, \(\frac{b}{2} = \frac{4}{\sqrt5}\)
\(⇒ b = \frac{8}{\sqrt5}\)
So, the Area ab \(= 2 \sqrt5 . \frac{8}{\sqrt5}\)
= 16