Question:

A rectangle has a length that is twice its height. If the perimeter of that rectangle is \(20\text{ in}\), what is its area?

Show Hint

If one side is a known multiple of the other, express both in one variable and use perimeter \(2(l+w)\) to solve quickly.
Updated On: Oct 3, 2025
  • \(400\text{ in}^2\)
  • \(1507\text{ in}^2\)
  • \(2509\text{ in}^2\)
  • \(103\text{ in}^2\)
  • \(\dfrac{200}{9}\text{ in}^2\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is

Solution and Explanation

Step 1: Set variables.
Let height \(= h\). Then length \(= 2h\).
Step 2: Use perimeter.
\(P = 2(\text{length} + \text{height}) = 2(2h + h) = 6h = 20 \Rightarrow h = \dfrac{10}{3}\text{ in}\).
Length \(= 2h = \dfrac{20}{3}\text{ in}\).
Step 3: Compute area.
\(A = (\text{length})(\text{height}) = \dfrac{20}{3} \cdot \dfrac{10}{3} = \dfrac{200}{9}\text{ in}^2\).
Final Answer:
\[ \boxed{\dfrac{200}{9}\ \text{in}^2} \]
Was this answer helpful?
0
0

Questions Asked in GRE exam

View More Questions