Step 1: Understanding the effects of increasing the width of a rectangle by 10%
The dimensions of the rectangle are \( L \) (length) and \( W \) (width), with \( L > W \). When the width \( W \) is increased by 10%, the new width becomes \( W' = 1.1W \), while the length \( L \) remains the same.
Step 2: Analyzing the impact on each option
Option (A): Perimeter increases by 10%
The perimeter of a rectangle is given by the formula:
\[
P = 2(L + W)
\]
When the width increases by 10%, the new perimeter becomes:
\[
P' = 2(L + 1.1W)
\]
This is not exactly a 10% increase. The increase in perimeter is not proportional to the increase in width. Therefore, this option is incorrect.
Option (B): Length of the diagonals increases by 10%
The diagonal \( d \) of a rectangle is given by the Pythagorean theorem:
\[
d = \sqrt{L^2 + W^2}
\]
When the width increases by 10%, the new diagonal is:
\[
d' = \sqrt{L^2 + (1.1W)^2}
\]
This increase is not guaranteed to be exactly 10%. The length of the diagonal increases, but not necessarily by 10%. Therefore, this option is incorrect.
Option (C): Area increases by 10%
The area \( A \) of a rectangle is:
\[
A = L \times W
\]
After increasing the width by 10%, the new area is:
\[
A' = L \times 1.1W = 1.1 \times L \times W
\]
This shows that the area increases by exactly 10%. Therefore, this option is correct.
Option (D): The rectangle becomes a square
A rectangle becomes a square only if the length and width are equal. Since only the width is increased by 10% and \( L > W \), this option is incorrect.
Therefore, the correct answer is Option (C): Area increases by 10%.