Question:
A random variable X has the following probability distributionX 0 1 2 3 4 5 6 7 P(X) 0 k 2k 2k 3k k2 2k2 7k2+k
then value of E(X) is:
A random variable X has the following probability distribution
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| P(X) | 0 | k | 2k | 2k | 3k | k2 | 2k2 | 7k2+k |
then value of E(X) is:
Updated On: Apr 26, 2024
- 1.66
- 2.66
- 3.66
- 4.66
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The Correct Option is C
Solution and Explanation
The correct option is(C):3.66
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