Question

A purified protein sample contains 10 µg of protein and has an enzyme activity of 1 mole of ATP synthesized/sec (1 unit). What is the specific activity of the final purified sample?

• A. 1,000 units/mg
• B. 10,000 units/mg
• C. 100,000 units/mg
• D. 1,000,000 units/mg

Hint:

Specific activity is a key measure in enzymology, representing the enzyme activity per amount of protein in a sample. Higher specific activity indicates greater enzyme purity.

Answer 1

The Correct Option is C

Specific activity is calculated using the formula: \[ \text{Specific Activity} = \frac{\text{Enzyme Activity (Units)}}{\text{Amount of Protein (mg)}} \] Given: - Enzyme activity = 1 unit (1 mole of ATP synthesized/sec)
- Amount of protein = 10 µg = 0.01 mg
Now, calculate the specific activity:
\[ \text{Specific Activity} = \frac{1 \text{ unit}}{0.01 \text{ mg}} = 100,000 \, \text{units/mg} \]
Conclusion: The specific activity of the final purified sample is 100,000 units/mg.