Question:
A projectile is thrown with initial velocity $v_{0}$ and angle $30^{\circ}$ with the horizontal. If it remains in the air for $1\, s$, what was its initial velocity?
A projectile is thrown with initial velocity $v_{0}$ and angle $30^{\circ}$ with the horizontal. If it remains in the air for $1\, s$, what was its initial velocity?
Updated On: Jun 14, 2022
- 19.6 m/s
- 9.8 m/s
- 4.9 m/s
- 1 m/s
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The Correct Option is B
Solution and Explanation
Time of flight $T=\frac{2 u \sin \theta}{g}$
Given, $u=v_{0},\, T=1\, s,$
$\theta=30^{\circ}, g=9.8\, m / s ^{2}$
$v_{0}=u=g=9.8\, m / s$
Given, $u=v_{0},\, T=1\, s,$
$\theta=30^{\circ}, g=9.8\, m / s ^{2}$
$v_{0}=u=g=9.8\, m / s$
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Concepts Used:
Motion in a Plane
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
Equations of Plane Motion
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,
- v = final velocity of the particle
- u = initial velocity of the particle
- s = displacement of the particle
- a = acceleration of the particle
- t = the time interval in which the particle is in consideration