Since the lens is silvered, it will act as a concave mirror, and the focal length \( f \) becomes negative.
The focal length of the mirror is \( f = -20 \, \text{cm} \).
Using the mirror formula:
\[
\frac{1}{f} = \frac{1}{u} + \frac{1}{v}
\]
where:
- \( f = -20 \, \text{cm} \),
- \( u = -25 \, \text{cm} \) (since the object is 25 cm from the mirror),
- \( v \) is the image distance we need to find.
Substitute the values:
\[
\frac{1}{-20} = \frac{1}{-25} + \frac{1}{v}
\]
Solving for \( v \), we get:
\[
\frac{1}{v} = \frac{1}{-20} - \frac{1}{-25} = -\frac{1}{100}
\]
Thus,
\[
v = -100 \, \text{cm}
\]
This means the image is formed 100 cm to the left of the system.