Question:

A particle of mass $m$ moves in the $XY$ plane with a velocity ' $v$ ' along the straight line $A B$. If the angular momentum of the particle with respect to origin $O$ is $L _{ A }$ when it is at $A$ and $L_{B}$ when it is at $B$, then

Updated On: Jul 5, 2022
  • $L_{A}>L_{B}$
  • $L_{A}=L_{B}$
  • the relationship between $L _{ A }$ and $L _{ B }$ depends upon the slope of the line $AB$
  • $L_{A} < L_{B}$
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The Correct Option is B

Solution and Explanation

From the definition of angular momentum, $\vec{ L }=\vec{ r } \times \vec{ p }=r m v \sin \phi(-\hat{ k })$
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Concepts Used:

Torque

Torque is a moment of force. Torque is measured as a force that causeque is also defined as the turning effect of force on the axis of rotation. Torque is chs an object to rotate about an axis and is responsible for the angular acceleration. Characterized with “T”.

How is Torque Calculated?

Torque is calculated as the magnitude of the torque vector T for a torque produced by a given force F

T = F. Sin (θ)

Where,

 r - length of the moment arm,

θ - the angle between the force vector and the moment arm.

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Types of Torque

Torque is of two types:

  1. Static torque
  2. Dynamic torque