Question

A particle is subjected to two simple harmonic motions along the x and y axes, described by x(t) = \(\alpha\)sin(2\(\omega\)t + π) and y(t) = 2\(\alpha\) sin(\(\omega\)t). The resultant motion is given by

• A. \(\frac{x^2}{\alpha^2}+\frac{y^2}{4\alpha^2}=1\)
• B. x²+y²=1
• C. \(y^2=x^2(1-\frac{x^2}{4\alpha^2})\)
• D. \(x^2=y^2(1-\frac{y^2}{4\alpha^2})\)

Answer 1

The Correct Option is D

The correct answer is (D) : \(y^2=x^2(1-\frac{x^2}{4\alpha^2})\)