Question:

A particle is moving with a constant speed $v$ in a circle. What is the magnitude of average velocity after half rotation ?

Updated On: Jan 16, 2024
  • $2v$
  • $\frac{2v}{\pi}$
  • $\frac{v}{2}$
  • $\frac{v}{2\pi}$
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The Correct Option is B

Solution and Explanation

We are given that a particle is moving with a constant speed $\nu$ in the circle so the time taken to cover the complete circle would be equal to $T = \frac{2\pi r}{\nu}$ hence the time taken to cover half the rotation would be equal to $T_{1/2} = \frac{2\pi r}{2\nu} = \frac{\pi r}{\nu}$ , hence the magnitude of average velocity after half rotation on would be equal to $\nu_{av} = \frac{2r}{\frac{\pi r}{\nu}} = \frac{2\nu}{\pi}$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration