To adhere to the fundamental requirement, each pair of cities, such as A and B, must have both morning and evening flights in both directions. This ensures that individuals from A or B can travel to the other city and return on the same day. Consequently, there should be a total of four flights connecting any pair of cities.
Regarding the selection of two cities from the total of ten cities, the number of ways to achieve this can be calculated using
\(=\frac{10\times9}{2}=45\)
Hence, the minimum number of flights that must be scheduled = 45 ×4 = 180.
Consider the ten cities labeled A through J, with A, B, and C identified as hubs and the remaining seven cities designated as non-hub cities. The condition specifies that any direct flight must originate and/or terminate at a hub.
Take city D as an example, which is a non-hub city. D should be connected to each of the hubs, A, B, and C. According to the previous solution, there must be four flights between D and each of A, B, and C. Therefore, from D, there must be a total of \(4 × 3 = 12\) flights connecting to the three hubs.
Similarly, for each of the other six non-hub cities, there must be 12 flights connecting each non-hub city with the three hubs. This results in a total of \(12 × 7 = 84\) flights linking a non-hub city with a hub. Additionally, the three hubs must be connected among themselves. As per the requirement of four flights between any pair of cities, there must be a total of \(4 × 3 = 12\) flights connecting any pair of hubs.
Hence, the minimum total number of flights that should be scheduled is 84 (connecting non-hub cities with hubs) + 12 (connecting hubs) = 96.
Given that G1 has cities A, B, and C, and G2, G3, and G4 have 3, 2, and 2 cities, respectively. According to the given conditions, a city in G2 cannot have a direct flight to a city in G3 or G4. To travel from a city in G2 to a city in G3 or G4, all cities in G2 must be connected to A. Subsequently, a person can travel from A to B or C to reach a city in G3 or G4.
Consequently, the 3 cities in G2 must be connected to A, requiring 4 flights between each pair of cities. This results in a total of 4 × 3 = 12 flights between cities in G2 and A. Considering the 2 cities in G3, there must be 2 × 4 = 8 flights connecting cities in G3 and B. Similarly, for the 2 cities in G4, there must be 2 × 4 = 8 flights connecting cities in G4 and C. Additionally, cities in G1 (A, B, and C) must be interconnected, requiring an extra 4 × 3 = 12 flights between these three cities.
Hence, the total minimum number of direct flights that must be scheduled is 12 (G2 to A) + 8 (G3 to B) + 8 (G4 to C) + 12 (interconnecting cities in G1) = 40.
The given information states that cities in G2 will be assigned to G3 or G4. However, this alone does not lead to a reduction in the number of flights, as cities in G2 still need to be connected to either B or C.
However, an additional piece of information is provided: there are now no flights between A and C. Consequently, the 4 flights that would have been scheduled in the previous case connecting A and C will not be scheduled.
Therefore, the maximum reduction in the number of flights can be 4.