Question

A motor cycle of mass 100 kg is moving with a velocity of 15 m/s on a circular path having radius of curvature 20 m. Then the centrifugal force acting on it is (Acceleration due to gravity = 10 m/s²)

• A. 225 N
• B. 1125 N
• C. 750 N
• D. 1055 N

Hint:

In circular motion, always use the formula \( F = \frac{m v^2}{r} \) to calculate the centrifugal force or centripetal force.

Answer 1

The Correct Option is B

The centrifugal force (also called centripetal force) is given by: \[ F = \frac{m v^2}{r} \] Substitute the given values \( m = 100 \, \text{kg} \), \( v = 15 \, \text{m/s} \), and \( r = 20 \, \text{m} \): \[ F = \frac{100 \times 15^2}{20} = \frac{100 \times 225}{20} = 1125 \, \text{N} \]
Thus, the centrifugal force is 1125 N.