The work done by the motor is equal to the potential energy required to lift the water:
\[
W = mgh,
\]
where \(m = 7560 \, \text{kg}\), \(g = 10 \, \text{m/s}^2\), and \(h = 100 \, \text{m}\). The power is the work done per unit time:
\[
P = \frac{W}{t}.
\]
Using the efficiency of the pump, the actual power is:
\[
P_{\text{actual}} = \frac{P}{\text{efficiency}} = \frac{4 \, \text{kW}}{0.7}.
\]