A manufacturer produces three products \(x,y,z\) which he sells in two markets. Annual sales are indicated below:Market Products I 10000 2000 18000 II 6000 20000 8000
(a)If unit sale prices of \(x,y\) and \(z\) are Rs 2.50,Rs 1.50 and Rs 1.00, respectively, find the total revenue in each market with the help of matrix algebra.
(b) If the unit costs of the above three commodities are Rs 2.00, Rs 1.00 and 50 paise respectively. Find the gross profit.
| Market | Products | ||
| I | 10000 | 2000 | 18000 |
| II | 6000 | 20000 | 8000 |
(b) If the unit costs of the above three commodities are Rs 2.00, Rs 1.00 and 50 paise respectively. Find the gross profit.
Solution and Explanation
(a) The unit sale prices of \(x, y\), and \(z\) are respectively given as Rs 2.50, Rs 1.50, and Rs 1.00. Consequently, the total revenue in market I can be represented in the form of a matrix as:
\(\begin{bmatrix}10000& 2000& 18000\end{bmatrix}\begin{bmatrix}2.50\\ 1.50\\ 1.00\end{bmatrix}\)
\(=10000\times2.50+2000\times1.50+18000\times1.00]\)
\(=25000+3000+18000\)
\(=46000\)
The total revenue in market II can be represented in the form of a matrix as:
\(\begin{bmatrix}6000& 20000& 8000\end{bmatrix}\begin{bmatrix}2.50\\ 1.50\\ 1.00\end{bmatrix}\)
\(=6000\times2.50+20000\times1.50+8000\times1.00\)
\(=15000+30000+8000\)
\(=53000\)
Therefore, the total revenue in market I is Rs 46000 and the same in market II is Rs 53000.
(b) The unit cost prices of x, y, and z are respectively given as Rs 2.00, Rs 1.00, and 50 paise.
Consequently, the total cost prices of all the products in market I can be represented in the form of a matrix as:
\(\begin{bmatrix}10000& 2000& 18000\end{bmatrix}\begin{bmatrix}2.00\\ 1.00\\ 0.50\end{bmatrix}\)
\(=10000\times2.00+2000\times1.00+18000\times0.50\)
\(=20000+2000+9000\)
\(=31000\)
Since the total revenue in market I is Rs 46000, the gross profit in this market is (Rs 46000−Rs 31000) Rs 15000.
The total cost prices of all the products in market II can be represented in the form of a matrix as:
\(\begin{bmatrix}6000& 20000& 8000\end{bmatrix}\begin{bmatrix}2.00\\ 1.00\\ 0.50\end{bmatrix}\)
\(=6000\times2.00+20000\times1.00+8000\times0.50\)
\(=12000+20000+4000\)
\(=Rs 36000\)
Since the total revenue in market II isRs 53000, the gross profit in this market is (Rs53000 − Rs 36000) Rs 17000.
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