Question:

A magnetic dipole of magnetic moment $6 \times 10^{-2} \, {Am^{2}}$ and moment of inertia $12 \times 10^{-6} \, {kg\, m^{2}}$ performs oscillations in a magnetic field of $2 \times 10^{-2} $ T. The time taken by the dipole to complete $20$ oscillations is $( \pi \simeq 3)$

Updated On: Apr 15, 2024
  • 36 s
  • 6 s
  • 12 s
  • 18 s
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The Correct Option is C

Solution and Explanation

Given, Magnetic moment $(M)=6 \times 10^{-2} \,A - m ^{2}$ Moment of inertia $(I)=12 \times 10^{-6} kg - m ^{2}$ Magnetic field $(B)=2 \times 10^{-2} T$ We know that. Time $(t)=2 \pi \sqrt{\frac{I}{M B}}$ $=2 \pi \sqrt{\frac{12 \times 10^{-6}}{6 . \times 10^{-2} \times 2 \times 10^{-2}}} $ $=2 \pi \sqrt{\frac{12 \times 10^{-2}}{12}} $ $=2 \pi \times 10^{-1}$ For 20 oscillation, Time $(t)=20 \times 2 \pi \times 10^{-1}$ $=12 s$
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